Units of electric flux are

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Electric flux $(\Phi_E)$ is defined as the product of the electric field $(E)$ and the area $(A)$ through which it passes,i.e.,$\Phi_E = E \cdot A

Vedclass · Accepted Answer

$N \cdot m^2 / C$

Vedclass · Answer

(C) Electric flux $(\Phi_E)$ is defined as the product of the electric field $(E)$ and the area $(A)$ through which it passes,i.e.,$\Phi_E = E \cdot A$.
Method $1$: Using the relation between electric field and potential,$E = -dV/dx$. The unit of electric field is $V/m$. Therefore,the unit of flux is $(V/m) \cdot m^2 = V \cdot m$.
Method $2$: Using the definition $E = F/q$. The unit of electric field is $N/C$. Therefore,the unit of flux is $(N/C) \cdot m^2 = N \cdot m^2 / C$.
Both $V \cdot m$ and $N \cdot m^2 / C$ are valid units for electric flux. However,given the options,$V \cdot m$ is a standard representation.

Similar Questions

If $\vec E = \frac{E_0 x}{a} \hat i$,then find the electric flux through the shaded area of the cube as shown in the figure,where the shaded face is at $x = a$.

Define electric flux.

If the number of electric lines of force emerging out of a closed surface is $1000$,then the charge enclosed by the surface is .......... $C$.

An electric field,$\overrightarrow{E} = \frac{2 \hat{i} + 6 \hat{j} + 8 \hat{k}}{\sqrt{6}} \ V/m$,passes through a surface of $4 \ m^2$ area having a unit normal vector $\hat{n} = \left( \frac{2 \hat{i} + \hat{j} + \hat{k}}{\sqrt{6}} \right)$. The electric flux through that surface is:

Three positive charges of equal value $q$ are placed at the vertices of an equilateral triangle. The resulting lines of force should be sketched as in:

Vedclass Test Series

Exam Paper Generator

Online Exam Module